2b. Because the coefficient of x is 4 3 , our calculations for y will be easier if the values of x are divisible by 3. So, we will let x = -3, 0, and 3. x y = 4 3 x - 4 (x, y) -3 y = 4 3 (-3) - 4 y=-4 - 4 y=-8 (-3, -8) 0 y = 4 3 (0) - 4 y = 0 - 4 y=-4 (0, -4) 3 y = 4 3 (3) - 4 y = 4 - 4 y = 0 (3, 0) Plot the points (-3, -8), (0, -4), and (3, 0). Since the points lie in a line, we draw the line through the points to obtain the graph of y = 4 3 x - 4. (3, 0) 2 4 (0, –4) (–3, –8) –2 –4 –2 –4 –6 –8 x y 2c. Let x = -2, 0, 1. x x - 2y = 4 (x, y) -2 -2 - 2y = 4 -2 - 2y + 2 = 4 + 2 -2y = 6 -2y -2 = 6 -2 y=-3 (-2, -3) 0 0 - 2y = 4 -2y = 4 -2y -2 = 4 -2 y=-2 (0, -2) 1 1 - 2y = 4 1 - 2y - 1 = 4 - 1 -2y = 3 -2y -2 = 3 -2 y=- 3 2 a1, - 3 2 b 212 Chapter 3 Linear Equations in Two Variables
hendricks_beginning_algebra_1e_ch1_3
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