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hendricks_beginning_algebra_1e_ch1_3

Section 1.2 Fractions Review 23 = 12 6 + 5 6 Simplify the product. = 12 + 5 6 Add the numerators and place over the common denominator. = 17 6 Simplify the numerator. 7d. We first convert each mixed number to an improper fraction, 4 1 12 = 49 12 and 1 9 14 = 23 14 . We find the LCD, as follows. 14 = 2 · 7 12 = 2 · 2 · 3 LCD = 2 · 2 · 3 · 7 = 84 4 1 12 - 1 9 14 = 49 12 - 23 14 = 49 12 · 7 7 - 23 14 · 6 6 = 343 84 - 138 84 = 343 - 138 84 = 205 84 = 2 37 84 Student Check 7 Add or subtract the fractions and simplify the result. a. 2 7 + 1 3 b. 5 24 - 1 30 c. 7 + 1 3 d. 6 3 16 - 4 9 20 Troubleshooting Common Errors Some common errors associated with fractions are shown next. �� ������������������������ ������������������ A problem and an incorrect solution are given. Provide the correct solution and an explanation of the error. 8a. Simplify 2 3 · 1 5 . �������������������������������������� ���������������������������������������������������������������� 2 3 · 1 5 = 2 3 · 5 3 1 5 · 3 3 We do not need to find the LCD when multiplying fractions, we can simply multiply the numerators and denominators. 2 3 · 1 5 = 2 · 1 3 · 5 = 2 15 10 15 3 3 15 = 30 225 = 2 15 Write each fraction as an improper fraction. Multiply each fraction by a form of 1 to obtain the LCD, 84. Simplify each product. Subtract the numerators and place over the common denominator. Simplify the numerator. Convert to a mixed number. Objective 8 ▶ Troubleshoot common errors. 5 = 0


hendricks_beginning_algebra_1e_ch1_3
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