The distributive property can be applied when there are more than two terms inside parentheses. We just multiply the factor by each term in parentheses. �� ������������������������ ������������������ Apply the distributive property to rewrite each expression. Simplify the result. 3a. 2(x + 4) 3b. 3(x - 5) 3c. 4(2x + 7) 3d. -5(x + 2) 3e. -3(x - 7) 3f. 8(2x + 3y - 5) 3g. -(6x - 9) 3h. 10 a1 5 x + 1 2 b �� Solutions�� 3a. 2(x + 4) = 2(x) + 2(4) Apply the distributive property. = 2x + 8 Simplify. 3b. 3(x - 5) = 3(x) - 3(5) Apply the distributive property. = 3x - 15 Simplify. 3c. 4(2x + 7) = 4(2x) + 4(7) Apply the distributive property. = 8x + 28 Simplify. 3d. -5(x + 2) = -5(x) + (-5)(2) Apply the distributive property. = -5x - 10 Simplify. 3e. -3(x - 7) = -3(x) - (-3)(7) Apply the distributive property. = -3x + 21 Simplify. 3f. 8(2x + 3y - 5) = 8(2x) + 8(3y) - 8(5) Apply the distributive property. = 16x + 24y - 40 Simplify. 3g. -1(6x - 9) = -1(6x) - (-1)(9) Distribute -1 to each term. = -6x + 9 Simplify. ������������ Multiplying by -1 changes the signs of the original terms in parentheses. 3h. 10 a1 5 x + 1 2 b = 10 a1 xb 5 + 10 a1 2 b Apply the distributive property. = 2x + 5 Simplify. Student Check 3 Apply the distributive property to rewrite each expression. Simplify the result. a. 5(x + 6) b. 7(x - 3) c. 2(3x + 1) d. -3(x + 2) e. -6(x - 4) f. 9(4x + 5y - 3) g. -(8x + 2) h. 15 a- 1 3 x + 2 5 b 74 Chapter 1 Real Numbers and Algebraic Expressions
hendricks_beginning_algebra_1e_ch1_3
To see the actual publication please follow the link above