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messersmith_power_intermediate_algebra_1e_ch4_7_10

EXAMPLE 1 Plot the points. a) (2, 5) b) (1, 4) c) a7 2 , 3b d) (5, 2) e) (0, 1.5) f) (4, 0) Solution To plot each point, move from the origin in the following ways: a) (2, 5): Move left 2 units then up 5 units. This point is in quadrant II. b) (1, 4): Move right 1 unit then down 4 units. This point is in quadrant IV. c) a7 2 , 3b: Think of 7 2 as 3 1 2 . Move right 3 1 2 units then up 3 units. This point is in quadrant I. d) (5, 2): Move left 5 units then down 2 units. This point is in quadrant III. y (2, 5) 5 Notice that negative x-values make you move e) (0, 1.5): The x-coordinate of 0 means that we don’t left, and negative y-values make you move down. x move in the x-direction (horizontally). From the origin, move up 1.5 units on the y-axis. This point is not in any quadrant. f) (4, 0): From the origin, move left 4 units. Since the y-coordinate is zero, we do not move in the y-direction (vertically). This point is not in any quadrant. , 3 72 (0, 1.5) 5 5 (1, 4) (4, 0) (5, 2) 5 YOU TRY 1 Plot the points. a) (3, 1) b) (2, 4) c) (0, 5) d) (2, 0) e) (4, 3) f) a1, 7 2 b Note The coordinate system should always be labeled to indicate how many units each mark represents. A solution of an equation in two variables is written as an ordered pair so that when the values are substituted for the appropriate variables we obtain a true statement. www.mhhe.com/messersmith SECTION 4.1 Introduction to Linear Equations in Two Variables 141


messersmith_power_intermediate_algebra_1e_ch4_7_10
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