Step 3: Complete the square: 1 2 (5) 5 2 a5 2 b 2 25 4 Add 25 4 to both sides of the equation. y2 5y 25 4 3 2 25 4 y2 5y 25 4 6 4 25 4 Get a common denominator. y2 5y 25 4 31 4 Add. Step 4: Factor: ay 5 2 b 2 31 4 c 5 2 is 1 2 (5), the coeffi cient of y, in the equation above. Step 5: Solve using the square root property. ay 5 2 b 2 31 4 y 5 2 A 31 4 Square root property y 5 2 131 2 Simplify. y 5 2 131 2 Add 5 2 to each side. Check the answers. The solution set is e 5 2 131 2 , 5 2 131 2 f . YOU TRY 3 Solve by completing the square. a) 4c2 8c 45 0 b) 2b2 6b 5 ANSWERS TO YOU TRY EXERCISES 1) a) w2 2w 1; (w 1)2 b) r2 18r 81; (r 9)2 2) a) {7, 3} b) 3) a) e 9 2 , 5 2 f b) e 3 2 119 2 , 3 2 119 2 f 618 CHAPTER 10 Quadratic Equations www.mhhe.com/messersmith
messersmith_power_introductory_algebra_1e_ch4_7_10
To see the actual publication please follow the link above