204 Chapter 3 Fractions and Mixed Numbers: Addition and Subtraction Using Fractions and Mixed Numbers in a Geometry Application Jason and Sara plan to paint a side of their house (Figure 3-5). a. How much area will they have to paint? b. They want to string Christmas lights around the triangular portion of the house.What length is required for the string of lights? Solution: a. The area of the side of the house is given by the sum of the rectangular area and the triangular area. Area of triangle ftb a12 2 1 21 a45 1 270 ft Area of rectangle 2 382 2 652 765 2 ft 2 12 ft 45 ft The total area is given by 270 ft . 12 ft2 The total area to paint is 652 . b. The perimeter of the triangle is found by adding the lengths of the sides. 1 25 2 ft 1 225 ft 45 ft 25 1 2 ft 25 1 2 ft 45 ft 95 2 2 ft 96 ft Jason and Sara will need 96 ft of lights. 1 2 ft 1 2 ft 2 or 382 1 2 ft2 a45 1 ftb a17 2 ftb 145 ft2 a8 1 2 ftb l w 6 1 ftb 1 2 145 ft2 112 ft2 1 2 bh Example 6 1 310 yd 13 yd 13 yd 1 310 yd 5 yd Answers 6. a. 184 yd2 of sod is needed. b. yd of fencing is needed. 5623 1 225 ft 1 225 ft 12 ft 45 ft 1 28 ft Figure 3-5 1 28 ft 45 ft Skill Practice 6. A homeowner wants to sod the yard and fence the perimeter as shown in the figure. a. How much sod (area) is required? b. How much fencing is required? 5 yd 12 yd Avoiding Mistakes In reality, Jason and Sara might want to overestimate the amount of paint needed so that they don’t run out of supplies during the job. For example: Triangle area 270 ft2 Rectangle area (45 ft)(10 ft) 450 ft2 Total area 270 ft2 450 ft2 720 ft2
miller_basic_college_math_3e_ch1_3
To see the actual publication please follow the link above