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Section 1.8 Problem-Solving Strategies 75 From Clayton to Oakley through Pearson, we divide 180 mi by 60-mph increments to determine the number of hours. Clayton Oakley Therefore, each route takes the same amount of time, 3 hr. Solving a Construction Application A rancher must fence the corral shown in Figure 1-11. However, no fencing is required on the side adjacent to the barn. If fencing costs $4 per foot, what is the total cost? 275 ft 200 ft 300 ft 200 ft 475 ft Solution: Read and familiarize: A figure is provided. Strategy With some application problems, it helps to work backward from your final goal. In this case, our final goal is to find the total cost. However, to find the total cost, we must first find the total distance to be fenced. To find the total distance, we add the lengths of the sides that are being fenced. Therefore, b ° 11450 ft2 1$4 per ft2 $5800 aTotal cost of fencing The total cost of fencing is $5800. total distance in feet ¢a cost per foot b 2 1 7 1 5 ft 200 ft 200 ft 475 ft 300 ft 1450 ft Barn Example 7 Time 180 mi 60 mph 3 hr 60 mi in 1 hr 60 mi in 1 hr 60 mi in 1 hr 180 mi Pearson Figure 1-11 Skill Practice 7. Alain wants to put molding around the base of the room shown in the figure. No molding is needed where the door, closet, and bathroom are located. Find the total cost if molding is $2 per foot. Answer 7. $124 Bathroom 3 ft Door 3 ft Closet 8 ft 20 ft 18 ft


miller_basic_college_math_3e_ch1_3
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