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miller_beginning_intermediate_algebra_4e_ch1_3

Section 2.2 Solving Linear Equations 115 Answers 4. {1} 5. {2.1} Step 4: Divide both sides by 2 to obtain a coefficient of 1 for p. Step 5: Check: 7 3 21 p 32 10 218 32 10 2152 10 10 16 2 2p 2 8 p The solution set is {8}. ✔ True Skill Practice Solve the equation. 4. 12 2 713 y2 Solving a Linear Equation Example 5 Solve the equation. Solution: 2.2y 8.3 6.2y 12.1 Step 1: The right- and left-hand sides are already simplified. Step 2: Subtract 2.2y from both sides to collect the variable terms on one side of the equation. Step 3: Subtract 12.1 from both sides to collect the constant terms on the other side. Step 4 : To obtain a coefficient of 1 for the y-term, divide both sides of the equation by 4. Step 5: Check: 2.2y 8.3 6.2y 12.1 2.215.12 8.3 6.215.12 12.1 11.22 8.3 31.62 12.1 19.52 19.52 2.2y 8.3 6.2y 12.1 2.2y 2.2y 8.3 6.2y 2.2y 12.1 8.3 4y 12.1 8.3 12.1 4y 12.1 12.1 20.4 4y 20.4 4 4y 4 5.1 y y 5.1 The solution set is {5.1}. ✔ True Skill Practice Solve the equation. 5. 1.5t 2.3 3.5t 1.9 TIP: In Examples 5 and 6 we collected the variable terms on the right side to avoid negative coefficients on the variable term.


miller_beginning_intermediate_algebra_4e_ch1_3
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