Tutorial on AC Power - Part 3
That's right. Q = sqrt(S2 - P2) = sqrt(6002 - 3782) = 466 kvars
A factory uses 220V commercial power. The principal users of power are a lighting load of 200 KW and an injection molding machine rated at 600 KVA. The molding machine has a power factor of .63 lagging and is 87% efficient in converting electrical energy to mechanical energy.
Below is the resulting power triangle for the machine.

What is the mechanical output power of the machine? Round your answer to the nearest horse power.
After you get the answer, please click on an option:
Go on to the next
part of the tutorial.
Go back to the main
menu.
© 1999 Thomas G. Cleaver. All rights reserved. |