Network Analysis

Tutorial on AC Power - Part 2

That's right. P = S x pf = 600 x .63 = 378 kW

A factory uses 220V commercial power. The principal users of power are a lighting load of 200 KW and an injection molding machine rated at 600 KVA. The molding machine has a power factor of .63 lagging and is 87% efficient in converting electrical energy to mechanical energy.

Below is the resulting power triangle for the machine.

What is Q for this power triangle? Round your answer to the nearest kilovar.

After you get the answer, please click on an option:
Go on to the next part of the tutorial.
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