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Organic Chemistry 4e Carey | |||||
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Allylic systems |
Chapter 10: Conjugation in Alkadienes and Allylic Systems |
Allylic systems
The positions
adjacent to C=C often show enhanced reactivity compared to simple alkanes
due to the proximity of the adjacent p system. Such positions are referred
as "allylic". Recall that the term "vinylic" is
used to described the atoms directly associated with the C=C unit.
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Highlight allylic hydrogen atoms Highlight allylic carbon atoms Highlight vinylic hydrogen atoms Highlight vinylic carbon atoms Reset colours |
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Highlight allylic hydrogen atoms Highlight allylic carbon atoms Highlight vinylic hydrogen atoms Highlight vinylic carbon atoms Reset colours |
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The p system of a double bond can stabilize an adjacent carbocation by donating electron density through resonance. Remember that delocalising charge is a stabilizing effect. This stabilisation is equivalent to that of two alkyl groups, so the allyl cation has similar stability to the 2-propyl cation. |
| Note that in the two resonance forms of the allylic cation, the positive charge is located on the terminal carbon atoms and never on the middle carbon. This is reflected in the resonance hybrid and the positive areas of the electrostatic potential shown to the right (blue). Note that either of the carbons with +ve charge could be attacked by a nucleophile. | ![]() |
Due to the stability of these allylic cations, they are readily formed as intermediates during chemical reactions, for example SN1 reactions of allylic halides.
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The p system of a double bond can also stabilize an adjacent radical through resonance. Remember that delocalising the radical is a stabilizing effect. |
Summary:
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FOR ALLYLIC BROMINATION |
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| Step 1 (Initiation)
Heat or uv light causes the weak halogen bond to undergo homolytic cleavage to generate two bromine radicals and starting the chain process. |
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| Step 2 (Propagation)
(a) A bromine radical abstracts a hydrogen to form HBr and an allyl radical, then (b) The allyl radical abstracts a bromine atom from another molecule of Br2 to form the allyl bromide product and another bromine radical, which can then itself undergo reaction 2(a) creating a cycle that can repeat. |
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| Step 3 (Termination)
Various reactions between the possible pairs of radicals allow for the formation of Br2 or the product, allyl bromide. These reactions remove radicals and do not perpetuate the cycle. |
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Substitution Reactions of Allyl Halides
Can you account for why the 3o alcohol is the major product ?Related reactions![]()
What does the fact that both the reactions shown give the same product mixture suggest ?