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Organic Chemistry 4e Carey | |||||
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Oxygen Nucleophiles |
Chapter 17: Aldehydes and Ketones. Nucleophilic Addition to C=O |
Formation of Hydrates
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| hydrate |
Summary
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| Step 1: An acid/base reaction. Since there is only a weak nucleophile we need to activate the carbonyl by protonating on O. |
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| Step 2: The nucleophilic O in the water attacks the electrophilic C in the C=O, breaking the p bond and giving the electrons to the positive O. |
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| Step 3: An acid/base reaction. Deprotonation of the oxonium ion neutralizes the charge giving the hydrate. |
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Reactions of Alcohols to give Acetals
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| hemi-acetal acetal |
Reaction type: Nucleophilic Addition then nucleophilic substitution
Summary
Related Reactions
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| Step 1: An acid/base reaction. Since there is only a weak nucleophile we need to activate the carbonyl by protonating on O. |
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| Step 2: The nucleophilic O in the alcohol attacks the electrophilic C in the C=O, breaking the p bond and giving the electrons to the positive O. |
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| Step 3: An acid/base reaction. Deprotonation of the alcoholic oxonium ion neutralizes the charge giving the hemi-acetal. Now we need to substitute the -OH by -OEt. |
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| Step 4: An acid/base reaction. In order for the -OH to leave we need to make it into a better leaving group by protonation. |
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| Step 5: Using the electrons from the other O, the leaving group departure is facilitated. |
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| Step 6: We now have what resembles a protonated ketone (compare with step 2). The nucleophilic O of the alcohol attacks the electrophilic C and the electrons of the p bond move to neutralize the charge on the positive O. |
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| Step 7: An acid/base reaction. Deprotonation of the alcoholic oxonium neutralizes the charge and produces the acetal product and regenerates the acid catalyst. |
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| The overall transformation required is ester to primary alcohol. This is a reduction of the ester, which requires LiAlH4, but that will reduce the ketone as well which we don't want. We can avoid this problem if we "change" the ketone to a different functional group first. Conceptually, this is like being able to put a cover (shown below) over the ketone while we do the reduction, then remove the cover. |
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| In reality, the "molecular cover" is a protecting group. In this example, we protect the ketone as an acetal (which is an ether and doesn't react with LiAlH4) |
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| Then we can reduce the ester to the primary alcohol. |
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| Finally we can remove the protecting group: |
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| Overall, this gives us the complete scheme:
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