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Organic Chemistry 4e Carey | |||||
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Reactions of Nitriles |
Chapter 20: Carboxylic Acid Derivatives. Nucleophilic Acyl Substitution |
Overview
versus
Examples of such nucleophilic systems are : H2O, ROH
| The protonation of a nitrile gives a structure that can
be redrawn in another resonance form that reveals the electrophilic
character of the C since it is a carbocation. |
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Summary
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| Step 1: An acid/base reaction. Since we only have a weak nucleophile so activate the nitrile, protonation makes it more electrophilic. |
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| Step 2: The water O functions as the nucleophile attacking the electrophilic C in the CºN, with the electrons moving towards the positive center. |
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| Step 3: An acid/base reaction. Deprotonate the oxygen that came from the water molecule. The remaining task is a tautomerization at N and O centers. |
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| Step 4: An acid/base reaction. Protonate the N gives us the -NH2 we need.... |
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| Step 5: Use the electrons of an adjacent O to neutralise the positive at the N and form the p bond in the C=O. |
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| Step 6: An acid/base reaction. Deprotonation of the oxonium ion reveals the carbonyl in the amide intermediate....halfway to the acid..... What about the rest ? |
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Reduction
of Nitriles
(for more detail see Chapter 22)
Summary
Reactions of RLi or RMgX with Nitriles
Summary:
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| Step 1: The nucleophilic C in the organometallic reagent adds to the electrophilic C in the polar nitrile group. Electrons from the CºN move to the electronegative N creating an intermediate imine salt complex. |
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| Step 2: An acid/base reaction. On addition of aqueous acid, the intermediate salt protonates giving the imine. |
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| Step 3: An acid/base reaction. Imines undergo nucleophilic addition, but require activation by protonation (i.e. acid catalysis) |
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| Step 4: Now the nucleophilic O of a water molecule attacks the electrophilic C with the p bond breaking to neutralize the change on the N. |
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| Step 5: An acid/base reaction. Deprotonate the O from the water molecule to neutralize the positive charge. |
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| Step 6: An acid/base reaction. Before the N system leaves, it needs to be made into a better leaving group by protonation. |
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| Step 7: Use the electrons on the O in order to push out the N leaving group, a neutral molecule of ammonia. |
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| Step 8: An acid/base reaction. Deprotonation reveals the carbonyl group of the ketone product. |
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