Preparation of Alkynes

Chapter 9 : Alkynes

 
Alkylation of Alkynes
Alkylation of terminal alkynes
Reaction Type: Acid / Base  and  Nucleophilic Substitution

Summary

MECHANISM FOR ALKYLATION OF ALKYNES
Step 1:
An acid / base reaction. The amide ion acts as a base removing the acidic terminal H to generate the acetylide ion, a carbon nucleophile.
S<sub>N</sub>2 alkylation of an acetylide ion
Step 2:
A nucleophilic substitution reaction. The carbanion reacts with the electrophilic carbon in the alkyl halide with loss of the leaving group, forming a new C-C bond.
What is the product of the reactions of CH3-CºC- with each of the following:
(a) 2-bromopropane CH3CCCH(CH3)2, 4-methyl-2-pentyne (d)  ethanol No S<sub>N</sub>2, but acid base to give EtO- and CH3CCH
(b) 1-iodooctane CH3(CH2)7CCCH3 = 2-undecyne (e)  ethyl tosylate CH3CCCH2CH3, the S<sub>N</sub>2 product since -OTs is a good leaving group
(c) (R)-2-bromohexane (S)-4-methyl-2-octyne (f)   bromobenzene No reaction, aryl halides don't undergo S<sub>N</sub>2 reactions

Related reactions:

Preparation of Alkynes via Elimination reactions
elimination of vicinal dihalide to an alkyne
elimination of geminal dihalide to an alkyne
Reaction Type: Elimination (E2)

Summary

What is the alkyne product from the reactions of the following with NaNH2 :
(a) 2,2-dibromopropane CH3CCH, propyne (c) 1,2-dibromohexane CH3(CH2)3CCH, 1-hexyne
(b) 1,1-dibromooctane CH3(CH2)6CCH = 1-octyne (d)  2,3-dibromohexane CH3(CH2)2CCCH3, 2-hexyne