Using Nitrogen Nucleophiles

Chapter 17: Aldehydes and Ketones. Nucleophilic Addition to C=O

Reactions of Primary Amine derivatives

                                                                      imine

Reaction type:  Nucleophilic Addition then Elimination

Summary

Question:
Why can't amine nucleophiles be used in strongly acidic media ? 

 

Related Reactions

NUCLEOPHILIC ADDITION OF A PRIMARY AMINE GIVING AN IMINE.
Step 1:
An acid/base reaction. Protonation of the carbonyl activates it and makes it more susceptible to attack by a neutral nucleophilic like the N of a primary amine.
formation of an imine
Step 2:
Attack of the N nucleophile at the electrophilic C of the C=O group with the electrons from the p bond going to the +ve O.
Step 3:
An acid/base reaction. Removal of the proton neutralizes the +ve charge on the N and forms the carbinolamine intermediate.
Step 4:
To form the imine we need to dehydrate. However, before -OH leaves it needs to be protonated, so a simple acid/base reaction.
Step 5:
Use the electrons of the N to help push out the leaving group, a neutral water molecule, this leaves us with an iminium ion.
Step 6:
An acid/base reaction. Deprotonation of the iminium N reveals the imine product and regenerates the acid catalyst.

 

Reactions of Primary Amine Derivatives

reactions of aldehydes and ketones with primary amine derivatives

Reaction type:  Nucleophilic Addition then Elimination

Summary

Related Reactions

Reactions of Secondary Amine Derivatives

preparation of enamines
                                                                          enamine

Reaction type:  Nucleophilic Addition then Elimination

Summary

Related Reactions
NUCLEOPHILIC ADDITION OF A SECONDARY AMINE GIVING AN ENAMINE.
Step 1:
An acid/base reaction. Protonation of the carbonyl activates it and makes it more susceptible to attack by a neutral nucleophilic like the N of a secondary amine.
formation of an enamine
Step 2:
Attack of the N nucleophile at the electrophilic C of the C=O group with the electrons from the p bond going to the +ve O.
Step 3:
An acid/base reaction. Removal of the proton neutralizes the +ve charge on the N and forms the carbinolamine intermediate.
Step 4:
To form the enamine we need to dehydrate. However, before -OH leaves it needs to be protonated, so a simple acid/base reaction.
Step 5:
Removal of a proton from an adjacent C allows the p bond to form and loss of the leaving group, a neutral water molecule, creating the enamine.