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Oxidation Reactions |
Chapter 17: Aldehydes and Ketones. Nucleophilic Addition to C=O |
Oxidation of Aldehydes
Summary
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| Part 1: Formation of the hydrate (mechanism) occurs first. |
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| Part 2: Now we essentially have an alcohol which reacts with the chromium species to form a chromate ester. |
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| Part 3: A base (here a water molecule) abstracts a proton from the chromate ester, the C=O forms and a Cr species leaves. This is really an E2 elimination reaction. Note the importance of the original aldehyde H... if its' missing, no oxidation can occur. |
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Reaction type: Oxidation -reduction via Nucleophilic addition
Summary
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| lactone |
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In this example the primary ethyl group migrates in preference to the methyl group |
Related Reactions
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| Step 1: An acid/base reaction. Protonation of the carbonyl activates it while creating a more reactive nucleophile, the percarboxylate. |
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| Step 2: Now the nucleophilic O attacks the carbonyl C with the electrons from the p bond going to the positive O. |
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| Step 3: Electrons from the O come back (this reforms the p bond of the C=O) and we migrate the C-C electrons to form a new C-O bond displacing the carboxylate as a leaving group. |
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| Step 4: Finally an acid/base reaction reveals the C=O and therefore the ester product. |
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