Oxygen Nucleophiles

Chapter 17: Aldehydes and Ketones. Nucleophilic Addition to C=O

Formation of Hydrates

equilibrium with water giving hydrates
                                                                  hydrate
Reaction type:  Nucleophilic Addition

Summary

Related Reactions
MECHANISM FOR THE ACID catalyzed FORMATION OF HYDRATES
Step 1:
An acid/base reaction. Since there is only a weak nucleophile we need to activate the carbonyl by protonating on O.
acid catalysed formation of a hydrate
Step 2:
The nucleophilic O in the water attacks the electrophilic C in the C=O, breaking the p bond and giving the electrons to the positive O.
Step 3:
An acid/base reaction. Deprotonation of the oxonium ion neutralizes the charge giving the hydrate.

 

Reactions of Alcohols to give Acetals

reaction with alcohols giving an acetal
                                                              hemi-acetal                                  acetal

Reaction type:  Nucleophilic Addition then nucleophilic substitution

Summary

cyclic acetal from ethylene glycol
cyclic acetal from 1,3-propanediol
Study Tip:
The important "piece" of an acetal is the central C which becomes the C of the carbonyl C=O. It can be recognized by looking for the C that is attached to two O atoms by single bonds.

Related Reactions

MECHANISM FOR THE ACID catalyzed FORMATION OF ACETALS
Step 1:
An acid/base reaction. Since there is only a weak nucleophile we need to activate the carbonyl by protonating on O.
Step 2:
The nucleophilic O in the alcohol attacks the electrophilic C in the C=O, breaking the p bond and giving the electrons to the positive O.
Step 3:
An acid/base reaction. Deprotonation of the alcoholic oxonium ion neutralizes the charge giving the hemi-acetal.  Now we need to substitute the -OH by -OEt.
Step 4:
An acid/base reaction. In order for the -OH to leave we need to make it into a better leaving group by protonation.
Step 5:
Using the electrons from the other O, the leaving group departure is facilitated. 
Step 6:
We now have what resembles a protonated ketone (compare with step 2).  The nucleophilic O of the alcohol attacks the electrophilic C and the electrons of the p bond move to neutralize the charge on the positive O.
Step 7:
An acid/base reaction. Deprotonation of the alcoholic oxonium neutralizes the charge and produces the acetal product and regenerates the acid catalyst.

Protecting Groups


The overall transformation required is ester to primary alcohol.  This is a reduction of the ester, which requires LiAlH4, but that will reduce the ketone as well which we don't want. We can avoid this problem if we "change" the ketone to a different functional group first. Conceptually, this is like being able to put a cover (shown below) over the ketone while we do the reduction, then remove the cover.
cartoon of a protecting group
In reality, the "molecular cover" is a protecting group. In this example, we protect the ketone as an acetal (which is an ether and doesn't react with LiAlH4)

Then we can reduce the ester to the primary alcohol.

Finally we can remove the protecting group:

Overall, this gives us the complete scheme: