| Chapter 4: Alcohols and Alkyl Halides |
SN1 mechanism
SN1 indicates a substitution, nucleophilic, unimolecular reaction, described by the expression rate = k [R-LG]
This pathway is a multi-step process with the following characteristics:
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Multi-step reactions have intermediates and a several transition states
(TS).
In an SN1 there is loss of the leaving group generates an intermediate carbocation which is then undergoes a rapid reaction with the nucleophile. The reaction profiles shown here are simplified and do not include the equilibria for protonation of the -OH. |
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The following issues are relevant to the SN1 reactions of alcohols:
Effect of R-
Reactivity order : (CH3)3C-
> (CH3)2CH- > CH3CH2-
> CH3-
In an SN1 reaction, the key step is the loss of the leaving group to form the intermediate carbocation. The more stable the carbocation is, the easier it is to form, and the faster the SN1 reaction will be. Some students fall into the trap of thinking that the system with the less stable carbocation will react fastest, but they are forgetting that it is the generation of the carbocation that is rate determining.
-LG
The only event in the rate determining step of the SN1 is breaking
the C-LG bond. For alcohols
it is important to remember that -OH is a very poor leaving. In the reactions
with HX, the -OH is protonated first to give an oxonium, providing the
much better leaving group, a water molecule (see scheme below).
Nu
Since the nucleophile is not involved in the rate determining step
of an SN1 reaction, the nature of the nucleophile is unimportant.
In the reactions of alcohols with HX, the reactivity trend of HI > HBr
> HCl > HF is not due to the nucleophilicity of the halide ion but the
acidity of HX which is involved in generating the leaving group prior to
the rate determining step.
Stereochemistry
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In an SN1, the nucleophile attacks the planar carbocation. Since there
is an equally probability of attack on either face there will be a loss
of stereochemistry at the reactive center and both possible products
will be observed.
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Since a carbocation intermediate is formed, there is the possibility
of rearrangements (e.g. 1,2-hydride or 1,2-alkyl shifts) to generate
a more stable carbocation (see later). This is usually indicated
by a change in the position of the halide compared to that of the original
-OH group, or a change in the carbon skeleton of the product when compared
to the starting material.
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| Step 1:
An acid/base reaction. Protonation of the alcoholic oxygen to make a better leaving group. This step is very fast and reversible. The lone pairs on the oxygen make it a Lewis base. Step 2:
Step 3:
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