| Chapter 19: Carboxylic Acids |

Summary

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| Step 1:
An acid/base reaction. Protonation of the carbonyl makes it more electrophilic. |
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| Step 2:
The alcohol O functions as the nucleophile attacking the electrophilic C in the C=O, with the electrons moving towards the oxonium ion, creating the tetrahedral intermediate. |
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| Step 3:
An acid/base reaction. Deprotonate the alcoholic oxygen. |
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| Step 4:
An acid/base reaction. Need to make an -OH leave, it doesn't matter which one, so convert it into a good leaving group by protonation. |
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| Step 5:
Use the electrons of an adjacent oxygen to help "push out" the leaving group, a neutral water molecule. |
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| Step 6:
An acid/base reaction. Deprotonation of the oxonium ion reveals the carbonyl in the ester product. |
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