THE ACID-BASE PROPERTIES OF WATER AND THE pH SCALE (15.2 15.3)
STUDY OBJECTIVES
- Write the ion product constant for the autoionization of water, and use
it to relate [H+] and [OH] in aqueous solutions.
- Describe the pH scale, and calculate pH from a knowledge of [H+]
or [OH].
- Carry out numerical calculations involving the relationships among [H+],
[OH], pH and pOH.
Autoionization and the Ion-Product of Water.
Pure water is itself a very weak electrolyte and ionizes according to the equation:
H2O
H+(aq)
+ OH(aq)
According to the Brønsted theory, the reaction is viewed as a proton
transfer from one water molecule to another.
| H2O(l) |
+ |
H2O(l) |
 |
H3O+(aq) |
+ |
OH(aq) |
| acid1 |
|
base2 |
|
acid2 |
|
base1 |
Since water can act as both an acid and a base, it is an amphoteric
substance.
This reaction is reversible and H2O, H3O+
and OH are in equilibrium. In pure water at 25°C, [H+]
= [OH] = 1.0 x 107
M. These are low concentrations and tell us that very few H2O molecules
are ionized, and that the equilibrium lies to the left.
At equilibrium, the product of the hydrogen ion concentration and hydroxide
ion concentration equals a constant called the ion-product constant for water,
Kw.
Kw = [H+][OH]
= (1.0 x 107)(1.0 x
107) = 1.0 x 1014
Like other equilibrium constants we treat Kw as unitless.
The value of Kw applies to all aqueous solutions at 25°C.
When an acid is added to water, the [H+] increases. Therefore,
the [OH] must decrease in order for Kw
to remain constant. In acidic solutions [H+] >
[OH]. Similarly, when a base is added to water, and [OH]
increases, then [H+] must decrease. In basic solutions
[OH] > [H+]. Acidic, basic, and
neutral solutions are characterized by the following conditions:
| neutral |
[H+] = [OH] |
| acidic |
[H+] > [OH] |
| basic |
[H+] < [OH] |
The ion product provides a useful relationship for aqueous solutions. If the
value of [H+] is known, then the concentration of OH
can be calculated. Similarly, the H+ ion concentration can
be calculated, if the value of [OH] is known. Example 15.3
illustrates this type of calculation. In Table 15.1 below each row corresponds
to a solution with the given H+ and OH
concentrations. The table covers the entire practical range of concentrations
found in aqueous solutions. Note that the product of the two concentrations
in all aqueous solutions is 1.0 x 1014.
EXAMPLE Using the Ion-Product Constant, Kw
The H+ ion concentration in a certain solution is 5.0
x 105 M. What is the OH
ion concentration?
x 10^ M
Correct!
Click a Hint button for help.
The ion-product constant of water is applicable to all aqueous solutions.
Kw = [H+][OH] = 1.0 x 1014
When [H+] is known, we can solve for [OH].
Calculation
[OH] = 2.0 x 1010 M
The pH Scale. The concentration of H+(aq)
in a solution can be expressed in terms of the pH scale. The pH of a solution
is defined as the negative logarithm of the hydrogen ion concentration.
pH = log [H+]
Recall that the logarithm of a number is the power to which 10 must be raised
in order to equal the number. For example, the logarithm of 100 is 2.0 because
raising 10 to the 2nd power gives 100.
100 = 102
log 100 = 2
The log of a fraction or number less than 1 is a negative number.
= 0.01 = 102
log 0.01 = 2
First, let's find the pH of a neutral solution. In pure water at 25°C; [H+]
= 1 x 107 M. Using the definition
of pH given above, take the log of the H+ ion concentration
first:
pH = log (1.0 x 107)
pH = (7.0) = 7.0
The pH of a neutral solution is 7.0.
Likewise, for an acidic solution where, for example, the H+
ion concentration is 1 x 105 M,
the pH is 5.0.
pH = log (1 x 105) = ( 5.0) = 5.0
All acidic solutions have a pH < 7.0.
When [H+] is not an exact power of 10, the pH is not a
round number. Take the following basic solution, for example, if [H+]
= 2.5 x 109 M, the pH is
pH = log (2.5 x 109) = (8.60)
pH = 8.60
Note that all basic solutions have a pH > 7.0. The pH values corresponding
to selected sets of H+(aq) and OH(aq)
concentrations are given in Table 15.1. In terms of pH, solutions that are acidic,
basic, and neutral are defined as follows:
| neutral |
pH = 7.0O |
| acidic |
pH < 7.0 |
| basic |
pH > 7.0 |
The pOH Scale. A scale just like the pH
scale has been devised for the hydroxide ion concentration, where
pOH = log [OH]
Just as the H+ ion and OH ion concentrations
are related by the ion-product constant of water, Kw, the
pH and pOH are also related.
Kw = [H+][OH] = 1.0 x 1014
pH + pOH = 14
The sum of the pH and pOH values of any solution is always 14 at 25°C.
You can see this in Table 15.1. Sum the pH and pOH for each set of H+
and OH concentrations, and see what you get.
It is also important to notice that a change in pH of one unit corresponds
to a 10-fold change in [H+]. As H+
drops from 108 to 109 M, for instance, the pH changes
from 8 to 9. A change of 2.0 pH units corresponds to a 100-fold change in H+
ion concentration. Never say "A pH of 2 is twice as acidic as a pH of 4." It
is really 100 times more acidic!
Table 15.1 Relationship of pH and pOH in Aqueous Solutions
|
| [H+] |
[OH] |
pH |
pOH |
Nature of Solution |
|
| 100 |
1014 |
0 |
14 |
acidic |
| 101 |
1013 |
1 |
13 |
acidic |
| 102 |
1012 |
2 |
12 |
acidic |
| 103 |
1011 |
3 |
11 |
acidic |
| 106 |
108 |
6 |
8 |
acidic |
| 107 |
107 |
7 |
7 |
neutral |
| 108 |
106 |
8 |
6 |
basic |
| 1011 |
103 |
11 |
3 |
basic |
| 1012 |
102 |
12 |
2 |
basic |
| 1013 |
101 |
13 |
1 |
basic |
| 1014 |
100 |
14 |
0 |
basic |
|
EXAMPLE pH and pOH
The OH ion concentration in a certain ammonia solution
is 7.2 x 104 M. What is the pOH
and pH?
The pOH is the negative logarithm of the OH ion concentration
pOH = log [OH]
Calculation
| pOH |
= log (7.2 x 104)= (3.14) |
| | = 3.14 |
The pH and pOH are related by
pH + pOH = 14.00
| pH |
= 14.00 pOH = 14.00 3.14 |
| | = 10.86 |
Changing pH Values to [H+].
Given the pH, how do we calculate the [H+]? Rearrange the
equation for pH:
pH = log [H+]
log [H+] = pH
taking the antilog of both sides:
antilog (log [H+]) = antilog (pH)
gives:
[H+] = 10pH
Any electronic calculator with a 10x key will easily make
the calculation of H+ ion concentrations from pH values.
Just enter pH for x and push 10x.
EXAMPLE H+ Ion Concentration from pH
What is the H+ ion concentration in a solution with a
pOH of 3.9?
x 10^ M
Correct!
Click a Hint button for help.
Recall that pH + pOH = 14. With the pOH given, the pH can be calculated, and
then the H+ ion concentration can be determined.
Calculation
pH = 14.0 pOH
pH = 14.0 3.9 = 10.1
Since pH is known, the hydrogen ion concentration is
[H+] = 10pH
[H+] = 1010.1 = 7.9 x 1011 M
EXAMPLE Comparing pH Values
The pH of many cola-type soft drinks is about 3.0. How many times greater is
the H+ concentration in these drinks than in neutral water?
The [H+] is about
times greater.
Correct!
Click a Hint button for help.
First write out the H+ ion concentrations in the cola drink
and in neutral water.
[H+]cola = 1.0 x
103 M, and [H+] neut
= 1.0 x 107 M.
Then the ratio is
Comment
Here is another approach. Since a change of 1.0 pH unit corresponds to a 10-fold
change in H+ concentration, then a change of 4.0 pH units
corresponds to 10 x 10 x
10 x 10 = 104 or a 10,000-fold
increase in H+ concentration.
OBJECTIVE CHECK
Complete the following questions to check your understanding of the material.
Select the check button to see if you answered correctly.
Calculate the concentration of OH ions in an HNO3
solution where [H+] = 0.0010 M.
The OH ion concentration in an ammonia solution is
7.5 x 103 M. What is the H+
ion concentration?
Calculate the concentration of H+ ions in an acid solution
with a pH of 2.29.
What is the concentration of OH ions in a NaOH solution
which has a pOH of 4.90?
The pH of solution A is 2.0 and the pH of solution B is 4.0. How many times
greater is the H+(aq) concentration in solution A than in
solution B?
The pH of a certain solution is 3.0. How many moles of H3O+(aq)
ions are there in 0.10 L of this solution?