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messersmith_power_basic_college_1e_ch4_7_10

Add 2 3 1 6 . Solution Step 1: Write down the LCD of 2 3 and 1 6 . LCD 6 Step 2: Rewrite each fraction with the LCD. 2 3 2 2 4 6 1 6 already has a denominator of 6. Step 3: Add. 2 3 1 6 4 6 1 6 4 1 6 5 6 These fractions are equivalent. Step 4: Ask yourself, “Is 5 6 in lowest terms?” Yes. So, 5 6 is the fi nal answer. EXAMPLE 1 Don’t just think about the LCD “in your head.” Write it on your paper so you can look at it! YOU TRY 1 Add 1 2 1 12 . Add. a) 5 12 2 8 b) 6 7 2 9 c) 2 15 1 6 3 10 Solution a) Step 1: Write down the LCD of 5 12 and 2 8 . LCD 24 Step 2: Rewrite each fraction with the LCD. 5 12 2 2 10 24 2 8 3 3 6 24 Step 3: Add. Equivalent fractions 5 12 2 8 10 24 6 24 10 6 24 16 24 Equivalent fractions Step 4: Ask yourself, “Is 16 24 in lowest terms?” No! Write it in lowest terms. 16 24 16 8 24 8 2 3 The fi nal answer is 2 3 . EXAMPLE 2 244 CHAPTER 4 Adding and Subtracting Fractions www.mhhe.com/messersmith


messersmith_power_basic_college_1e_ch4_7_10
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